document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166979>Question 1166979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that you have 7 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards with replacement. Round your answers to four decimal places.\r<BR>\n" );
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document.write( "G1 = the first card drawn is green<BR>\n" );
document.write( "G2 = the second card drawn is green\r<BR>\n" );
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document.write( "a.  P(G1 and G2) = \r<BR>\n" );
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document.write( "b.  P(At least 1 green) =\r<BR>\n" );
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document.write( "c.  P(G2|G1) = \r<BR>\n" );
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document.write( "d.  Are G1 and G2 independent? \r<BR>\n" );
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document.write( "They are independent events<BR>\n" );
document.write( "They are dependent events </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791533 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791533\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> for both green it is (7/12)(7/12) with replacement or 49/144, or 0.3403.\r<BR>\n" );
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document.write( "at least 1 green is 1-0 green probability. For 0 green for both cards it is (5/12)^2 or 25/144, so the answer is 119/144 or 0.8264 probability.<BR>\n" );
document.write( "That is also the 0.3403 above + 2 (7/12)(5/12) or 70/144 or 0.4861<BR>\n" );
document.write( "That plus 0.3403 is 0.8264.\r<BR>\n" );
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document.write( "Given G1 is green the probability G2 is green is 7/12 with replacement. Nothing has changed, and the trials would be independent, in that what happened on the first doesn't affect the second. </SPAN>\n" );
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