document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166941>Question 1166941</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose the average length of stay in a chronic disease hospital of a certain type of patient is 60 days with a standard deviation of 15.if it is reasonable to assume  an approximately normal distribution of lengths of stay,find the probability that a randomly selected patient form this group will have a length of stay. \r<BR>\n" );
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document.write( "A) less than 48 days <BR>\n" );
document.write( "B) greater than 52 days <BR>\n" );
document.write( "C) between 40 and 50 days <BR>\n" );
document.write( "D) between 30 and 60 days  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791527 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "the first is z < -12/15 or z<-0.8 with probability of 0.2119\r<BR>\n" );
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document.write( "for the others, z is > -8/15 or probability of 0.7031\r<BR>\n" );
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document.write( "between 40 and 50 days, 0.1613<BR>\n" );
document.write( "this is z between -1.33 and -0.667<BR>\n" );
document.write( "also on calculator 2nd VARS 2normalcdf (40,50,60,15) ENTER\r<BR>\n" );
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document.write( "D is 0.4772 probability (between z=-2 and z=0) </SPAN>\n" );
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