document.write( "Question 1166908: Huntington's disease is a hereditary ailment caused by a recessive gene. If both parents carry the gene but do not have the disease, there is a 0.25 probability that an offspring will fall victim to the condition. A newly wed couple finds through genetic testing that they both carry the gene (but do not have the disease). If they intend to have four children, find the probability of the event that at least three of the children get the disease. \n" ); document.write( "
Algebra.Com's Answer #791481 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! ====H====h \n" ); document.write( "H---HH----Hh \n" ); document.write( "h---hH----hh \n" ); document.write( "for three of the children it is 4(1/4)^3*(1/4)=4/256 or 1/64 \n" ); document.write( "for all four it is (1/4)^2=1/256 \n" ); document.write( "the answer is the sum or 5/256. \n" ); document.write( " |