document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166823>Question 1166823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A truck heads north at a constant speed of 22m/s. A car leaves 20 minutes later heading north along the same road and travelling at a constant speed of 28 m/s. Determine how long the car travels until it catches up to the truck.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v=d%2Ft ALIGN=MIDDLE  ALT=\"v=d%2Ft\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "20 mins = 1200 seconds, both vehicles will have the same d\r<BR>\n" );
document.write( "\n" );
document.write( "I've found a solution on how to find the time, but I'm struggling to solve for t  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28t=22%28t%2B1200%29 ALIGN=MIDDLE  ALT=\"28t=22%28t%2B1200%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791357 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791357\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Only two hints:\r<BR>\n" );
document.write( "\n" );
document.write( "In 1200 seconds, the two vehicles are <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=22%28m%2Fs%29%2A1200%2As=26400%2Ameters ALIGN=MIDDLE  ALT=\"22%28m%2Fs%29%2A1200%2As=26400%2Ameters\"   DISABLED_style= \"max-width:90%; height:auto;\" > apart.\r<BR>\n" );
document.write( "\n" );
document.write( "The approach rate of the two cars is  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=28-22=6 ALIGN=MIDDLE  ALT=\"28-22=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >, in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=meters%2Fsecond ALIGN=MIDDLE  ALT=\"meters%2Fsecond\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "---\r<BR>\n" );
document.write( "\n" );
document.write( "Handle the formula properly.  Look carefully at your (single) step.\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=v=d%2Ft ALIGN=MIDDLE  ALT=\"v=d%2Ft\"   DISABLED_style= \"max-width:90%; height:auto;\" >, if v is for speed, d is for distance, t is for time.<BR>\n" );
document.write( "If you solve this for t, then what will you show?\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Now if you have v=6 in meters per second, and d=26400 meters, then, you should understand clearly how to find the time for the catch-up.<BR>\n" );
document.write( "-<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=d%2Fv ALIGN=MIDDLE  ALT=\"t=d%2Fv\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=t=26400%2F6 ALIGN=MIDDLE  ALT=\"t=26400%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" >-------and if you are watching the units carefully, you see this is  4400 seconds.  In HOURS this will be  about 1.222 hours.<BR>\n" );
document.write( "1 hour 13 minutes </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );