document.write( "Question 1166761: Joseph is in the business of manufacturing phones. He must pay a daily fixed cost of $1000 to rent the building and equipment, and also pays a cost of $50 per phone produced for materials and labor. Make a table of values and then write an equation for C, in terms of p, representing total cost, in dollars, of producing p phones in a given day. \n" ); document.write( "
Algebra.Com's Answer #791296 by Theo(13342)\"\" \"About 
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the daily fixed cost is 1000 dollars.
\n" ); document.write( "the per phone cost is 50 dollars per phone.
\n" ); document.write( "the total cost for the day is equal to 1000 + 50p.
\n" ); document.write( "p represents the number of phones produced for the day.
\n" ); document.write( "when C represents the total cost, the equation is:
\n" ); document.write( "C = 1000 + 50p.
\n" ); document.write( "when p = 1, C = 1000 + 50 * 1 = 1050
\n" ); document.write( "when p = 10, C = 1000 + 50 * 10 = 1500
\n" ); document.write( "when p = 50, C = 1000 + 50 * 50 = 3500
\n" ); document.write( "when p = 100, C = 1000 + 50 * 100 = 6000.\r
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\n" ); document.write( "\n" ); document.write( "the equation can be graphed as shown below:\r
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\n" ); document.write( "\n" ); document.write( "you can make a table of values.
\n" ); document.write( "you just have to decide what values you want to be in the table.
\n" ); document.write( "the equation tells you the total cost for the day, depending on the number of phones produced.\r
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