document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166571>Question 1166571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A grocery store counts the number of customers who arrive during an hour. The average over a year is 29 customers per hour. Assume the arrival of customers follows a Poisson distribution. (It usually does.)<BR>\n" );
document.write( "Find the probability that at least one customer arrives in a particular one minute period. Round your answer to 3 decimals.<BR>\n" );
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document.write( "Find the probability that at least two customers arrive in a particular 5 minute period. Round your answer to four decimals.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791291 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> it is proportional to time so expect 29/60 in a minute<BR>\n" );
document.write( "find the probability that 0 will come in that time and subtract from 1.<BR>\n" );
document.write( "p(0)=e^(-29/60)=0.6167<BR>\n" );
document.write( "so p(1 or more) is the complement or 0.3833 or 0.383..\r<BR>\n" );
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document.write( "in 5 minutes expect 29/12<BR>\n" );
document.write( "so look for p(0) and p(1), add and subtract from 1<BR>\n" );
document.write( "p(0)=e^(-29/12)=0.0892<BR>\n" );
document.write( "p(1)=e^(-29/12)*29/12^1/1=0.2156<BR>\n" );
document.write( "Those add to 0.3048<BR>\n" );
document.write( "subtract from 1 and get 0.6952. </SPAN>\n" );
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