document.write( "Question 108499: a rectangle has a length twice its width. A square with the same area has a side 2 units longer than the width of the rectangle. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #79129 by stanbon(75887)\"\" \"About 
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a rectangle has a length twice its width.
\n" ); document.write( "A square with the same area has a side 2 units longer than the width of the rectangle.
\n" ); document.write( "Find the dimensions of the rectangle.
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\n" ); document.write( "Let width of rectangle be \"x\"
\n" ); document.write( "Then length of rectangle is \"2x\"
\n" ); document.write( "Area of rectangle is 2x^2
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\n" ); document.write( "Square area = (side)^2 = 2x^2
\n" ); document.write( "Side of square = xsqrt(2)
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\n" ); document.write( "EQUATION:
\n" ); document.write( "side ofsquare = width of rectangle + 2
\n" ); document.write( "xsqrt(2) = x+2
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "2x^2 = x^2+4x+4
\n" ); document.write( "x^2-4x-4=0
\n" ); document.write( "x = [4 +- sqrt(16-4*-4)]/2
\n" ); document.write( "x = [4 +- sqrt(32)]/2
\n" ); document.write( "x = [2 +- 2sqrt(2)]
\n" ); document.write( "x = 2(1+sqrt(2)) or approximately 4.828...(this is the width of the rectangle)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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