document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166744>Question 1166744</A>: <I><SPAN STYLE=\"word-break: break-all;\"> On a canoe and camping trip, a group of Scouts decided to canoe downriver, set up camp, then canoe back to their starting point. The current stayed constant the whole time.\r<BR>\n" );
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document.write( "The Scouts canoed downstream (with the current) for 33.25 miles before stopping to camp. This took them 3.5 hours.\r<BR>\n" );
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document.write( "After camping, the Scouts canoed upstream (against the current) for the same 33.25 miles. This took them 9.5 hours. \r<BR>\n" );
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document.write( "Let x be the rate the Scouts travel in still water (with no current).\r<BR>\n" );
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document.write( "Let y be the rate of the current, such that:\r<BR>\n" );
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document.write( " 	Distance	Rate	Time<BR>\n" );
document.write( "Downstream	        (x+y)\r<BR>\n" );
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document.write( "  	 <BR>\n" );
document.write( "Upstream	 	(x-y)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #791279 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=791279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3.5 hours for 33.25 miles is 9.5 mph<BR>\n" );
document.write( "9.5 hours for 33.25 miles is 3.5 mph\r<BR>\n" );
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document.write( "x+y=9.5 mph<BR>\n" );
document.write( "x-y=3.5 mph<BR>\n" );
document.write( "2x=13 mph<BR>\n" );
document.write( "x=6.5 mph speed in still water<BR>\n" );
document.write( "y=3 mph current. </SPAN>\n" );
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