document.write( "Question 1166681: You roll two six-sided dice. What is the probability that the sum will be odd or a multiple of three? Round your answer to the nearest tenth of a percent. \n" ); document.write( "
Algebra.Com's Answer #791215 by themasterofcircuits(27)\"\" \"About 
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Let A be the sum is odd
\n" ); document.write( "Let B be the sum is a multiple of three\r
\n" ); document.write( "\n" ); document.write( "P(A or B)=P(A)+P(B)-P(A and B)\r
\n" ); document.write( "\n" ); document.write( "Possible odd sums: 3,5,7,9,11\r
\n" ); document.write( "\n" ); document.write( "3: (1,2) or (2,1)
\n" ); document.write( "5: (1,4), (4,1), (3,2), or (2,3)
\n" ); document.write( "7: (2,5), (5,2), (3,4), (4,3), (6,1), or (1,6)
\n" ); document.write( "9: (3,6), (6,3), (5,4), or (4,5)
\n" ); document.write( "11: (5,6),(6,5)\r
\n" ); document.write( "\n" ); document.write( "This could occur 18 times out of 36 dice roll possibilities.\r
\n" ); document.write( "\n" ); document.write( "So, P(A) = \"1%2F2\" or 0.5 or 50% \r
\n" ); document.write( "\n" ); document.write( "Possible multiples of 3:\r
\n" ); document.write( "\n" ); document.write( "3: (1,2) or (2,1)
\n" ); document.write( "6: (1,5), (5,1), (2,4), (4,2), (3,3)
\n" ); document.write( "9: (3,6), (6,3), (5,4), or (4,5)
\n" ); document.write( "12: (6,6)\r
\n" ); document.write( "\n" ); document.write( "This could occur 12 times out of 36 dice roll possibilities.\r
\n" ); document.write( "\n" ); document.write( "So, P(B) = \"1%2F3\" or 0.33 or 33%\r
\n" ); document.write( "\n" ); document.write( "Now, we need to find the possibilities they have in common. They are:\r
\n" ); document.write( "\n" ); document.write( "3: (1,2) or (2,1)
\n" ); document.write( "9: (3,6), (6,3), (5,4), or (4,5)\r
\n" ); document.write( "\n" ); document.write( "This could occur 6 times out of 36 dice roll possibilities.\r
\n" ); document.write( "\n" ); document.write( "So, P(A and B) = \"1%2F6\" or 0.166 or 16.6%\r
\n" ); document.write( "\n" ); document.write( "Since P(A or B)=P(A)+P(B)-P(A and B):\r
\n" ); document.write( "\n" ); document.write( "P(A or B) = \"1%2F2\"+\"1%2F3\"-\"1%2F6\"=\"2%2F3\"\r
\n" ); document.write( "\n" ); document.write( "Rounded to the nearest tenth of a percent: P(A or B) = 66.7%
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