document.write( "Question 1166630: A company president flew 1110 miles in a corporate jet but returned in a smaller plane that could fly only half as fast. If the total travel time was 9 hours, find the speeds of the planes.
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Algebra.Com's Answer #791183 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! x hours going \n" ); document.write( "9-x hours returning \n" ); document.write( "time to go 1110 miles is 1110/s1, where s1 is speed of jet \n" ); document.write( "time to go 1110 miles is 1110/s2, where s2 is speed of jet\r \n" ); document.write( "\n" ); document.write( "so x=1110/s1 \n" ); document.write( "9-x=1110/s2 \n" ); document.write( "1110=s1x \n" ); document.write( "1110=s2(9-x) \n" ); document.write( "therefore, s1x=s2(9-x) \n" ); document.write( "but s1=2s2 \n" ); document.write( "so 2s2x=s2(9-x) \n" ); document.write( "and 2x=9-x \n" ); document.write( "and 3x=9 \n" ); document.write( "so x=3 hours going there with speed 1110/3=370 mph in jet \n" ); document.write( "and 6 hours returning at 1110 miles or 185 mph in smaller plane. \n" ); document.write( " |