document.write( "Question 1166635: James is ⅓ the age of his father, Steve. The two have a combined age of 68.
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Algebra.Com's Answer #791138 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Instead of doing your problem for you, I'll do one exactly like it with\r\n" );
document.write( "different numbers.  Below is the problem I will do for you.  Use it as a\r\n" );
document.write( "model to solve yours by.  It's done step-by-step just like yours,\r\n" );
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\n" ); document.write( "James is ¼ the age of his father, Steve. The two have a combined age of 75.
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document.write( "James is ¼ the age of his father, Steve.  \r\n" );
document.write( "   |   | |                          |\r\n" );
document.write( "   J   = ⅓                          S\r\n" );
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document.write( "Getting it together\r\n" );
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document.write( "   J   = ¼S\r\n" );
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document.write( "The two, James and Steve, have a combined age of 75.  \r\n" );
document.write( "           |    |    |               |            |\r\n" );
document.write( "           J    +    S               =           75\r\n" );
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document.write( "Getting it together\r\n" );
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document.write( "   J + S = 75\r\n" );
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document.write( "So we have:\r\n" );
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document.write( "\"system%28J=expr%281%2F4%29S%2C+J%2BS=75%29\"    \r\n" );
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document.write( "Substitute ¼S for J in\r\n" );
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document.write( "     J + S = 68\r\n" );
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document.write( "\"expr%281%2F4%29S+%2B+S+=75\"\r\n" );
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document.write( "Multiply through by 4\r\n" );
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document.write( "\"S%2B4S=300\"\r\n" );
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document.write( "\"5S=300\"\r\n" );
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document.write( "\"S=60\"\r\n" );
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document.write( "J = ¼S = ¼(60) = 15\r\n" );
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document.write( "How old is James?  15\r\n" );
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document.write( "How old is Steve?  60\r\n" );
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document.write( "Now do yours the exact same way.\r\n" );
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document.write( "Edwin
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