document.write( "Question 1166619: The length of a rectangle is three inches more than its width. It’s area is 130 in2. Find the width and length of the rectangle.\r
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Algebra.Com's Answer #791128 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "width: w
\n" ); document.write( "length: w+3
\n" ); document.write( "area: w(w+3)=130

\n" ); document.write( "If a formal algebraic solution is required, then

\n" ); document.write( "\"w%28w%2B3%29=130\"
\n" ); document.write( "\"w%5E2%2B3w-130=0\"
\n" ); document.write( "\"%28w-10%29%28w%2B13%29=0\"
\n" ); document.write( "\"w=10\" OR \"w=-13\"

\n" ); document.write( "Reject the solution w=-13 because it makes no sense in the problem.

\n" ); document.write( "ANSWER: width = w = 10; length = w+3 = 13.

\n" ); document.write( "Note that to solve the problem using formal algebra, you had to factor that quadratic equation, which means finding two numbers whose difference is 3 and whose product is 130.

\n" ); document.write( "But that's what the original problem asked you to do.... So the formal algebra didn't save you any work.

\n" ); document.write( "So if formal algebra is not required, simply look at the area of 130 and see that it is 13 times 10; 13 is 3 more than 10, so you have the answer, and in only a few seconds.

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