document.write( "Question 1166618: The perimeter of a rectangle is 48 cm and its area is 135 cm^2. Find the length and the breadth/width of the rectangle.\r
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Algebra.Com's Answer #791127 by ikleyn(52787)\"\" \"About 
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document.write( "    L + W = 48/2 = 24 cm\r\n" );
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document.write( "    L*W = 135  cm^2,   or\r\n" );
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document.write( "    w*(24-W) = 135\r\n" );
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document.write( "    24W - W^2 = 135\r\n" );
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document.write( "    W^2 - 24W + 135 = 0\r\n" );
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document.write( "Factor left side\r\n" );
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document.write( "    (W-15)*(W-9) = 0\r\n" );
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document.write( "There are two roots,  W = 15  and  W = 9.\r\n" );
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document.write( "The dimensions of the rectangle are 9 cm (the width) and 15 cm (the length).       ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "To see million of similar solved problems, look into the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Problems on the area and the dimensions of a rectangle\r
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\n" ); document.write( "\n" ); document.write( "    - Three methods to find the dimensions of a rectangle when its area and the difference of two dimensions are given \r
\n" ); document.write( "\n" ); document.write( "in this site.\r
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\n" ); document.write( "\n" ); document.write( "Also,  you have this free of charge online textbook in ALGEBRA-I in this site\r
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\n" ); document.write( "\n" ); document.write( "The referred lesson is the part of this online textbook under the topic
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\n" ); document.write( "\n" ); document.write( "Save the link to this online textbook together with its description\r
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\n" ); document.write( "\n" ); document.write( "Free of charge online textbook in ALGEBRA-I
\n" ); document.write( "https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson\r
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\n" ); document.write( "\n" ); document.write( "to your archive and use it when it is needed.\r
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