document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=16209>Question 16209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 123. The second number is 9 less than two times the first number. The third number is 6 more than three times the first number. Find the three numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7911 by </B><A HREF=/tutors/aboutme.mpl?userid=pwac><B>pwac(253)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=pwac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7911\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= first number<BR>\n" );
document.write( "2x-9=second number<BR>\n" );
document.write( "3x+6=third number so if we add these terms together<BR>\n" );
document.write( "x+2x-9+3x+6=123<BR>\n" );
document.write( "6x-3=123 add 3 to both sides<BR>\n" );
document.write( "6x=126 divide both sides by 6<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "2x-9=33<BR>\n" );
document.write( "3x+6=69<BR>\n" );
document.write( "21+33+69=123 correct<BR>\n" );
document.write( "Pete </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );