document.write( "Question 1166488: In a triangle, the sum of the measures of the first and the second angles is twice of the measure of the third angle. If the measure of the second angle is 10° less than the measure of the third angle, then find the measures of the three angles. \n" ); document.write( "
Algebra.Com's Answer #791005 by josgarithmetic(39630)\"\" \"About 
You can put this solution on YOUR website!
\r\n" );
document.write( "first            x\r\n" );
document.write( "second          t-10\r\n" );
document.write( "third            t\r\n" );
document.write( "SUM             180\r\n" );
document.write( "\r\n" );
document.write( "\"x%2Bt-10=2t\"\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "\"x=10%2B2t-t\"
\n" ); document.write( "\"x=10%2Bt\"
\n" ); document.write( "Using this for x, sum of measures of interior angles:
\n" ); document.write( "\"%28t%2B10%29%2B%28t-10%29%2Bt=180\"\r
\n" ); document.write( "\n" ); document.write( "\"3t=180\"\r
\n" ); document.write( "\n" ); document.write( "\"t=60\"\r
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "---------------------------------------------\r\n" );
document.write( "The measures of the three angles:\r\n" );
document.write( "first        70\r\n" );
document.write( "second       50\r\n" );
document.write( "third        60\r\n" );
document.write( "--------------------------------------------\r\n" );
document.write( "
\n" ); document.write( "
\n" );