document.write( "Question 1166481: A salesman drives from Ajax to Barrington, a distance of 120 mi, at a steady speed. He then increases his speed by 15 mi/h to drive the 163 mi from Barrington to Collins. If the second leg of his trip took 3 min more time than the first leg, how fast was he driving between Ajax and Barrington? \n" ); document.write( "

Algebra.Com's Answer #790998 by ikleyn(52817) $\"\"$ $\"About$

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document.write( "From the condition, you have this \"time\" equation\r\n" );
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document.write( "     -  = ,  or\r\n" );
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document.write( "     -  = .\r\n" );
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document.write( "where x is the average speed under the question, in miles per hour.\r\n" );
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document.write( "To find x, first multiply both sides by  20x*(x+15);  reduce it to the standard form quadratic equation and then solve it.\r\n" );
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