document.write( "Question 1166450: C is the midpoint of AB​, D is the midpoint of AC​, E is the midpoint of AD​, F is the midpoint of ED​, G is the midpoint of EF​, and H is the midpoint of DB. If DC=56​, what is​ GH? \n" ); document.write( "
Algebra.Com's Answer #790980 by Edwin McCravy(20060)\"\" \"About 
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document.write( "We mark the line off with 32 marks, with A at 0 and B at 32.\r\n" );
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document.write( "C is the midpoint of AB​,\r\n" );
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document.write( "So we mark C at the 16 marker.\r\n" );
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document.write( "D is the midpoint of AC,\r\n" );
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document.write( "So we mark D at the 8 marker.\r\n" );
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document.write( "E is the midpoint of AD,\r\n" );
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document.write( "So we mark E at the 4 marker.\r\n" );
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document.write( "F is the midpoint of ED,\r\n" );
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document.write( "So we mark F at the 6 marker.\r\n" );
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document.write( "G is the midpoint of EF,\r\n" );
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document.write( "So we mark G at the 5 marker.\r\n" );
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document.write( "H is the midpoint of DB,\r\n" );
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document.write( "We observe that D is at 8, and that B is at 32. So their midpoint is at\r\n" );
document.write( "their average, (8+32)/2 = 20  \r\n" );
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document.write( "So we mark H at the 20 marker.\r\n" );
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document.write( "If DC=56​, what is​ GH?\r\n" );
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document.write( "D is at 8 and C is at 16.  That's 16-8=8 units on our scale.  Since DC=56, \r\n" );
document.write( "Each of the units on our scale here counts 56/8=7 on the scale of the\r\n" );
document.write( "problem. \r\n" );
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document.write( "G is at 5, and H is at 20.  That's 20-5=15 units on our scale, and since\r\n" );
document.write( "each unit on our scale is 7 units on the scale of the problem, the answer is\r\n" );
document.write( "15∙7 = 105 on the scale of the problem.   \r\n" );
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document.write( "Edwin
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