document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166434>Question 1166434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The Acme Candy Company claims that 60% of the jawbreakers it produces weigh more than 0.4<BR>\n" );
document.write( "ounces. Suppose that 800 jawbreakers are selected at random from the production lines. Use the<BR>\n" );
document.write( "Range Rule of Thumb to determine whether it is statistically significant for this sample of 800 to<BR>\n" );
document.write( "contain 494 jawbreakers that weigh more than 0.4 ounces? Consider as significant any result that<BR>\n" );
document.write( "differs from the mean by more than 2 standard deviations. Show all work (using Range Rule of<BR>\n" );
document.write( "Thumb) required to obtain your answer. Clearly state all important values involved.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790952 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790952\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The point estimate is 494/800=0.6175<BR>\n" );
document.write( "two tail test<BR>\n" );
document.write( "z=(phat-p)/sqrt(p*(1-p)/n)<BR>\n" );
document.write( "=0.0175/sqrt (.24/800); sqrt term=0.0173<BR>\n" );
document.write( "z=1.01<BR>\n" );
document.write( "fail to reject Ho because |z|<1.96. The true percentage could be 60%.<BR>\n" );
document.write( "p-value=0.31 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );