document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166391>Question 1166391</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Willie left the science museum and traveled west at an average speed of 30km/h. Gabriella left two hours later in the opposite direction at an average speed of 35km/h. Find the number of hours Gabriella needs to travel before they are 255km apart </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790897 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790897\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The distance apart when Gabriella leaves is 60 km, 2*2Willie's speed.<BR>\n" );
document.write( "They have to be 255 km apart.  Their combined speed is 65 km/h in opposite directions<BR>\n" );
document.write( "195/65=3 hours Gabriella has to travel<BR>\n" );
document.write( "in 3 hours goes 105 km.<BR>\n" );
document.write( "W. had gone 5 hours at 30 km/h, and that is 150 km<BR>\n" );
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