document.write( "Question 108407: solve following systems by substitution\r
\n" ); document.write( "\n" ); document.write( "4x-12y=5
\n" ); document.write( "-x+3y=-1\r
\n" ); document.write( "\n" ); document.write( "x=-3y+1\r
\n" ); document.write( "
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\n" ); document.write( "\n" ); document.write( "4(1-3y)+12y=5
\n" ); document.write( "4-12y+12y=5
\n" ); document.write( " 4x=5\r
\n" ); document.write( "\n" ); document.write( "Double checking to see if I did these right.
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #79082 by elima(1433) $\"\"$ $\"About$

You can put this solution on YOUR website!
The answer is going to be , no solution. When it is worked out, you cancel both variables.
\n" ); document.write( "You are close;
\n" ); document.write( "4x-12y=5
\n" ); document.write( "-x+3y=-1
\n" ); document.write( "=================
\n" ); document.write( "-x=-1-3y
\n" ); document.write( "x=1+3y
\n" ); document.write( "================
\n" ); document.write( "4(1+3y)-12y=5
\n" ); document.write( "4+12y-12y=5
\n" ); document.write( " $\"4%2Bcross%2812y%29-cross%2812y%29=5\"$
\n" ); document.write( "4=5
\n" ); document.write( "no solution
\n" ); document.write( ":) \n" ); document.write( "

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