document.write( "Question 1166273: d) The arrival rate of customers arriving at a bank counter follows a Poisson distribution with a mean rate of 4 per 10 minutes interval. Find the probability that
\n" ); document.write( " i. Exactly 0 customer will arrive in 10 minutes interval
\n" ); document.write( " ii. Exactly 2 customers will arrive in 10 minutes interval
\n" ); document.write( "iii. At most 2 customers will arrive in 10 minutes interval
\n" ); document.write( " iv. At least 3 customers will arrive in 10 minutes interval
\n" ); document.write( " (e) In a mainframe computer centre, execution time of programs follows an exponential distribution. The average execution time of the programs is 5 minutes. Find the probability that the execution time of programs is:
\n" ); document.write( " i. Less than 4 minutes
\n" ); document.write( " ii. More than 6 minutes
\n" ); document.write( "

Algebra.Com's Answer #790764 by themasterofcircuits(27)\"\" \"About 
You can put this solution on YOUR website!
d.)\r
\n" ); document.write( "\n" ); document.write( "The Poisson distribution is as follows: \"P%28x%2Cu%29=%28e%5E%28-u%29%2Au%5Ex%29%2Fx%21\"\r
\n" ); document.write( "\n" ); document.write( "Here, u is the mean, or 4 in this case.\r
\n" ); document.write( "\n" ); document.write( "i.) \"P%280%2C4%29=%28e%5E%28-4%29%2A4%5E0%29%2F0%21\" = 0.01832\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "ii.) \"P%282%2C4%29=%28e%5E%28-4%29%2A4%5E2%29%2F2%21\" = 0.14653\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "iii.) \"P%28x%3C=2%29=P%28x=0%29%2BP%28x=1%29%2BP%28x=2%29\" = \"P%280%2C4%29%2BP%281%2C4%29%2BP%282%2C4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"P%280%2C4%29=%28e%5E%28-4%29%2A4%5E0%29%2F0%21\" = 0.01832\r
\n" ); document.write( "\n" ); document.write( "\"P%281%2C4%29=%28e%5E%28-4%29%2A4%5E1%29%2F1%21\" = 0.07326\r
\n" ); document.write( "\n" ); document.write( "\"P%282%2C4%29=%28e%5E%28-4%29%2A4%5E2%29%2F2%21\" = 0.14653\r
\n" ); document.write( "\n" ); document.write( "\"P%28x%3C=2%29\" = 0.01832+0.07326+0.14653 = 0.23811\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "iv.) \"P%28x%3E=3%29=1-P%28x%3C3%29=1-P%28x%3C=2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"1-P%28x%3C=2%29\" = 1-0.23811=0.76819\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "e.) I have done d.) for you. e.) is the same idea, except you need to use the Exponential Distribution, which is a special case of the Poisson Distribution.\r
\n" ); document.write( "\n" ); document.write( "The exponential distribution is given by: \"P%28x%2Cu%29=%281%2Fu%29%2Ae%5E%28-x%2Fu%29\"\r
\n" ); document.write( "\n" ); document.write( "The letter cutoff in the exponential is an 'x'.\r
\n" ); document.write( "\n" ); document.write( "Good luck!\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );