document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166247>Question 1166247</A>: <I><SPAN STYLE=\"word-break: break-all;\">             In a large hospital an average of 3 out of every 5 patients ask for water with their meal. A random sample of 10 customers is selected. Assuming a binomial distribution, find the probability that i. Exactly 6 patients ask for water with their meal                                                               ii. At most 4 patients ask for water with their meal                                       iii. At least 3 patients ask for water with their meal                                       iv. Find the mean of this distribution                                                             v. Find the standard deviation of this distribution.                                 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790741 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790741\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> binomial with n=10 p=0.6<BR>\n" );
document.write( "mean is np=6<BR>\n" );
document.write( "variance is np(1-p)=6*0.4=2.4<BR>\n" );
document.write( "sd is sqrt(V)=1.55\r<BR>\n" );
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document.write( "exactly 6 is 10C6*0.6^6*0.4^4=0.2508<BR>\n" );
document.write( "At most 4 is 0,1,2,3,4 and that probability is binomcdf(10,0.6,4) or 0.1662<BR>\n" );
document.write( "At least 3 patients ask for water<BR>\n" );
document.write( "That is everyone but 0,1,2.  That probability (for 0,1,2) is 0.0123, so the answer is 1-0.0123 or 0.9877\r<BR>\n" );
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