document.write( "Question 1166227: Joan has one solution that is 18% acid and a second solution that is 43% acid how many liters of each should she mix together in order to get an 80 liters solutions that is 26.5% acid \n" ); document.write( "
Algebra.Com's Answer #790709 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let x equal the number of liters of the first solution. \n" ); document.write( "let y equal the number of liters of the second solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have 2 equations that need to be solved simultaneously. \n" ); document.write( "they are: \n" ); document.write( "x + y = 80 \n" ); document.write( ".18 * x + .43 * y = .265 * 80\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of the first equation by .18 and simplify both equations to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ".18 * x + .18 * y = 14.4 \n" ); document.write( ".18 * x + .43 * y = 21.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract the first equation from the second to get: \n" ); document.write( ".25 * y = 6.8 \n" ); document.write( "solve for y to get: \n" ); document.write( "y = 6.8 / .25 = 27.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since x + y = 80, then x must be equal to 80 - 27.2 = 52.8. \n" ); document.write( "you have x = 52.8 and y = 27.2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + y = 52.8 + 27.2 = 80 which is correct. \n" ); document.write( ".18 * x + .43 * y = .18 * 52.8 + .43 * 27.2 = 21.2 which is correct. \n" ); document.write( "21.2 / 80 = .265 = 26.5% which is also correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the solution is confirmed to be good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that she needs to mix 52.8 liters of the 18% solution and 27.2 liters of the 43% solution to get a solution that an 80 liter solution that is 26.5% acid.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |