document.write( "Question 1166019: a committee of three people is selected at random from a sec system of six teachers, four parents of students, and seven alumni.
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Algebra.Com's Answer #790651 by ikleyn(52812)\"\" \"About 
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document.write( "the denominator is the number of ways to choose 3 from (6+4+7) = 17, which is  \"C%5B17%5D%5E3\" = \"%2817%2A16%2A15%29%2F%281%2A2%2A3%29\" = 680.\r\n" );
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document.write( "all teachers is  \"C%5B6%5D%5E3\" = \"%286%2A5%2A4%29%2F%281%2A2%2A3%29\" = 20 ways.\r\n" );
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document.write( "So the answer to (a) is  P = \"20%2F680\" = 0.029412.\r\n" );
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document.write( "no teachers is  \"C%5B4%2B7%5D%5E3\" = \"C%5B11%5D%5E3\" = \"%2811%2A10%2A9%29%2F%281%2A2%2A3%29\" = 165 ways.\r\n" );
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document.write( "So the answer to (b) is  P = \"165%2F680\" = 0.242647.\r\n" );
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