document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166118>Question 1166118</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You and two friends decided to to to Wendy's now suppose that instead you go to McDonald's which is recently filled approximately 88.3% of the orders correctly. what is the probability that.<BR>\n" );
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document.write( "a. all three orders will be filled correctly<BR>\n" );
document.write( "b. none of the three will be filled correctly<BR>\n" );
document.write( "c. at lease two of the three will be filled correctly<BR>\n" );
document.write( "d. what are the mean and standard deviation of he binomial distribution used in a through interpret these values. \r<BR>\n" );
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document.write( "I only need a and d answered </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790650 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790650\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a, is 0.883^3=0.6885<BR>\n" );
document.write( "b. is 0.117^3=0.0016<BR>\n" );
document.write( "c. at least 2 of 3 means all (0.6885) and 2 of the 3 (3*0.883^2*0.117=0.2737 for probability 0.9621 (I rounded at the end; rounding earlier would give 0.9622).<BR>\n" );
document.write( "d. the mean is np=3*0.883=2.649<BR>\n" );
document.write( "variance is np(1-p)=2.649*0.117=0.3099<BR>\n" );
document.write( "sd is sqrt (V)=0.5567 </SPAN>\n" );
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