document.write( "Question 108430: RAY HAS $7.60 IN QUARTERS AND DIMES. IN ALL, HE HAS 40 COINS. HOW MANY COINS OF EACH KIND DOES HE HAVE? \n" ); document.write( "
| Algebra.Com's Answer #79065 by checkley71(8403)      You can put this solution on YOUR website! D+Q=40 OR D=40-Q \n" ); document.write( ".10D+.25Q=7.60 \n" ); document.write( ".10(40-Q)+.25Q=7.60 \n" ); document.write( "4-.10Q+.25Q=7.60 \n" ); document.write( ".15Q=7.60-4 \n" ); document.write( ".15Q=3.60 \n" ); document.write( "Q=3.60/.15 \n" ); document.write( "Q=24 NUMBER OF QUARTERS \n" ); document.write( "40-24=16 NUMBER OF DIMES. \n" ); document.write( "PROOF \n" ); document.write( ".10*16+24*.25=7.60 \n" ); document.write( "1.60+6=7.60 \n" ); document.write( "7.60=7.60 \n" ); document.write( " \n" ); document.write( " |