document.write( "Question 1166146: Ques-1_(The lifetime of 20,000 flashlight batteries are normally distributed,
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document.write( "with a mean of 370 days and a standard deviation of 30 days. How
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document.write( "many batteries can be expected to last less than 325 days?)\r
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document.write( "Ques-2_(The natural log of income has a normal distribution with mean 10.35
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document.write( "and variance 2.5. What is the probability that a person has income
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document.write( "below $10,000?) \n" );
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Algebra.Com's Answer #790647 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! ln 10000=9.21 \n" ); document.write( "so want z<(9.21-10.35)/sqrt 2.5 \n" ); document.write( "z<-1.14/1.58 \n" ); document.write( "z< -0.72 \n" ); document.write( "that has probability of 0.2358\r \n" ); document.write( "\n" ); document.write( "the first one z=(325-370)/30 or -45/30 or -1.5 \n" ); document.write( "that probability is 0.0668--for some reason I had the wrong number earlier. \n" ); document.write( "unrounded, multiply that by 20000 to get 1336.14 or 1336 batteries. \n" ); document.write( " |