document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1166096>Question 1166096</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mitzi shoots an arrow from an initial height of 2 meters, the arrow reaches its maximum height of 20 meters after it has flown a distance of 60 meters.\r<BR>\n" );
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document.write( "Write a quadratic function to represent the height of the arrow as a function of its distance. Use fraction, no decimals.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790595 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ax^2+bx+c=f(x)<BR>\n" );
document.write( "ordered pair 1 is (0, 2)<BR>\n" );
document.write( "so c=2<BR>\n" );
document.write( "for 2 it is (60, 20)<BR>\n" );
document.write( "so 3600x+60b+2=20<BR>\n" );
document.write( "the value of x=-b/2a at the vertex so that is 60=-b/2a<BR>\n" );
document.write( "-120a=b<BR>\n" );
document.write( "therefore -30b+60b+2=20<BR>\n" );
document.write( "30b=18<BR>\n" );
document.write( "b=3/5<BR>\n" );
document.write( "a=-1/200<BR>\n" );
document.write( "and (-1/200)x^2+(3/5)x+2=f(distance) ANSWER<BR>\n" );
document.write( "(0, 2) works<BR>\n" );
document.write( "(60, 20) works<BR>\n" );
document.write( "and vertex x value is -b/2a or -3/5/-1/100 or 60 for x, which works\r<BR>\n" );
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document.write( " </SPAN>\n" );
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