document.write( "Question 1166093: A jogger star from one end of a 11 mile nature trail at 8:00 A.M. One hour later, a cyclist starts from the other end of the trail and rides toward the jogger. If the rate of the jogger is 6 mph and the rate of the cyclist is 9 mph, at what time will the two meet? \n" ); document.write( "

Algebra.Com's Answer #790573 by ikleyn(52775) $\"\"$ $\"About$

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document.write( "At 9:00 am, the distance between them is 11-6 = 5 miles.\r\n" );
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document.write( "Their rate of approaching is  6+9 = 15 miles per hour.\r\n" );
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document.write( "Hence, the travel time after  9:00 am is   =   of an hour = 20 minutes.    \r\n" );
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document.write( "It means that they meet at 9:20 am.    ANSWER\r\n" );
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\n" ); document.write( "For simple Travel @ Distance problems, see introductory lessons \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "They are written specially for you.\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.\r
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\n" ); document.write( "\n" ); document.write( "Become an expert in this area.\r
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