document.write( "Question 1166080: The length of a rectangle is two less than half the width. Four times the length is eight less than twice the perimeter. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #790557 by josgarithmetic(39632)\"\" \"About 
You can put this solution on YOUR website!
L, length
\n" ); document.write( "w, width\r
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\n" ); document.write( "\n" ); document.write( "First sentence, \"L=w%2F2-2\"\r
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\n" ); document.write( "\n" ); document.write( "Second sentence, \"4L=2%28L%2Bw%29-8\"\r
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\n" ); document.write( "\n" ); document.write( "Maybe you can do the rest on your own.\r
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\n" ); document.write( "\n" ); document.write( "---\r
\n" ); document.write( "\n" ); document.write( "First Sentence equation \"2L=w-4\"
\n" ); document.write( "\"2L-w=-4\"\r
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\n" ); document.write( "\n" ); document.write( "Second Sentence equation \"4L=2L%2B2w-8\"
\n" ); document.write( "\"3L=2w-8\"
\n" ); document.write( "\"3L-2w=-8\"\r
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\n" ); document.write( "\n" ); document.write( "Revised System: \"system%282L-w=-4%2C3L-2w=-8%29\"\r
\n" ); document.write( "\n" ); document.write( "One way to go from here, is multiply first equation by 2, and subtract the \"first\" from \"second\".\r
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\n" ); document.write( "\n" ); document.write( "\"system%284L-2w=-8%2C3L-2w=-8%29\"
\n" ); document.write( "\"L=0\"-----------------------makes no sense.\r
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\n" ); document.write( "\n" ); document.write( "-----rechecking------\r
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\n" ); document.write( "\n" ); document.write( "Problem as given is wrong. No Solution!\r
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\n" ); document.write( "\n" ); document.write( "-----REDO-----------------
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\n" ); document.write( "\n" ); document.write( "\"system%28L=w%2F2-2%2C4L=2%28L%2Bw%29-8%29\"
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\n" ); document.write( "\"system%28w-2L=4%2Cw-L=4%29\"-----------impossible.......NO SOLUTION
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