document.write( "Question 1166048: Two brothers can do a job together in 6 hours. Working alone, the younger brother takes 2 hours longer than his older brother how long does each boy take when doing the job alone? \n" ); document.write( "
Algebra.Com's Answer #790521 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " RATE JOB/HOURS\r\n" ); document.write( "\r\n" ); document.write( "young 1/(y+2)\r\n" ); document.write( "\r\n" ); document.write( "old 1/y\r\n" ); document.write( "\r\n" ); document.write( "combined 1/6\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "--\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( ". \n" ); document.write( ".\r \n" ); document.write( "\n" ); document.write( "Younger brother, 17.08 hours alone \n" ); document.write( "Older brother, 11.08 hours alone \n" ); document.write( " |