document.write( "Question 1165890: Given a normal distribution with μ = 100 and σ = 10, if you select a sample of n = 25, what is the probability that the sample mean is\r
\n" ); document.write( "\n" ); document.write( "a. less than 95?\r
\n" ); document.write( "\n" ); document.write( "b. between 95 and 97.5?\r
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\n" ); document.write( "\n" ); document.write( "c. above 102.2?\r
\n" ); document.write( "\n" ); document.write( "d. There is a 65% chance that the sample mean is above what value?
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Algebra.Com's Answer #790363 by Boreal(15235)\"\" \"About 
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z=(x bar-mu)/sigma/sqrt(n)
\n" ); document.write( "<95 is (95-100)/10/5, and that is -5/2 or -2.5. Probability is 0.0062\r
\n" ); document.write( "\n" ); document.write( "between 95 and 97.5 is between z=-2.5 and -1.5, since the SEM is 2. That probability is 0.0606.
\n" ); document.write( "above 102.2 is z>2.2/2 or 1.1. Probability is 0.1357\r
\n" ); document.write( "\n" ); document.write( "the 35th percentile is at z=-0.39
\n" ); document.write( "so 65% of the area is above that
\n" ); document.write( "-0.39=(x-100)/2
\n" ); document.write( "-0.78=x-100
\n" ); document.write( "x=99.22
\n" ); document.write( "so 65% chance the sample mean is above 99.2 (rounded)\r
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