document.write( "Question 1165824: Mark, Lex, and Bren can finish a job 12,16, and 19 hours, respectively. Mark and Lex worked together for 4 hours. Lex got tired so Bren worked in place of him until the job is finished. How long did Mark work? \n" ); document.write( "
Algebra.Com's Answer #790327 by Boreal(15235) You can put this solution on YOUR website! in one hour, Mark does 1/12, Lex 1/16, and Bren 1/19 of the job \n" ); document.write( "In 4 hours, Mark did 4/12, Lex 4/16 \n" ); document.write( "That is 1/3 + 1/4 of the job or 7/12 \n" ); document.write( "Mark needs to work x more hours to do x/12, and Bren x hours to do x/19 \n" ); document.write( "that sum is 5/12 \n" ); document.write( "(x/12)+(x/19)=5/12 \n" ); document.write( "multiply by 228, \n" ); document.write( "19x+12x=95 \n" ); document.write( "31x=95 \n" ); document.write( "x=3.06 hours\r \n" ); document.write( "\n" ); document.write( "so Mark worked 7.06 hours and did 58.8% of the job \n" ); document.write( "Lex worked 4 hours and did 25% of the job \n" ); document.write( "Bren worked 3.06 hours and did 3.06/19 or 16.1% of the job \n" ); document.write( "Within rounding error, this is the 100% \n" ); document.write( " |