document.write( "Question 1165757: Mike has 19 coins in his pocket worth a total of $2.35. He only has nickels, dimes and quarters. There are 2 more dimes than nickels. How many of each coin type does Mike have?\r
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Algebra.Com's Answer #790295 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Mike has 19 coins in his pocket worth a total of $2.35. He only has nickels, dimes and quarters. There are 2 more dimes than nickels. How many of each coin type does Mike have?
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Let number of nickels be N
\n" ); document.write( "Then number of dimes = N + 2, and number of quarters = 19 - (N + N + 2) = 19 - 2N - 2 = 17 - 2N
\n" ); document.write( "We then get: .05N + .1(N + 2) + .25(17 - 2N) = 2.35
\n" ); document.write( ".05N + .1N + .2 + 4.25 - .5N = 2.35
\n" ); document.write( ".05N + .1N - .5N = 2.35 - 4.45
\n" ); document.write( "- .35N = - 2.1
\n" ); document.write( "Number of nickels, or
\n" ); document.write( "You should now be able to find the number of dimes, and quarters! \n" ); document.write( "
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