document.write( "Question 1165586: According to Newton’s law of cooling, the temperature of an object changes at a rate proportional to the difference in
\n" ); document.write( "temperature between the object and the outside medium. If an object whose temperature is 70OF is placed in a medium whose
\n" ); document.write( "temperature is 20O and is found to be 40O after 3 minutes, what will its temperature be after 6 minutes?
\n" ); document.write( "a. 25OF b. 28OF c. 31OF d. 34OF \n" ); document.write( "

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\n" ); document.write( "According to Newton’s law of cooling, the temperature of an object changes at a rate proportional to the difference in temperature between the object and the outside medium. If an object whose temperature is 70OF is placed in a medium whose temperature is 20O and is found to be 40O after 3 minutes, what will its temperature be after 6 minutes?
\n" ); document.write( "a. 25OF b. 28OF c. 31OF d. 34OF
\n" ); document.write( "

Newton's law of cooling formula:  where:  = time (t) at a COOLED temperature (3 minutes, in this case)\r\n" );
document.write( "                                                                     = TEMPERATURE (T) at a given time (t) (400^oF, in this case)\r\n" );
document.write( "                                                                     = SURROUNDING temperature (200^oF, in this case)\r\n" );
document.write( "                                                                     = ORIGINAL/INITIAL temperature (700^oF, in this case)\r\n" );
document.write( "                                                                     = CONSTANT or COOLING rate (Unknown, in this case)\r\n" );
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document.write( "     In this case, we 1st have to determine the value of k, and so: \r\n" );
document.write( "\r\n" );
document.write( ", where:  = time (t) at a COOLED temperature (6 minutes, in this case)\r\n" );
document.write( "                                     = TEMPERATURE (T) at a given time (t) (Unknown, in this case)\r\n" );
document.write( "                                     = SURROUNDING temperature (200^oF, in this case)\r\n" );
document.write( "                                     = ORIGINAL/INITIAL temperature (700^oF, in this case)\r\n" );
document.write( "                                     = CONSTANT or COOLING rate (, in this case)\r\n" );
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document.write( "                                    \r\n" );
document.write( "   Temperature, 6 minutes after, or

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