document.write( "Question 108369This question is from textbook Intermediate Algebra
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document.write( ": The speed of a bicyclist is 10mph faster than the speed of a walker. If the bicyclist travels 26 miles in the same amount of time that the walker travel 6 miles the speed of the bicyclist. \n" );
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Algebra.Com's Answer #79022 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! The speed of a bicyclist is 10 mph faster than the speed of a walker. If the bicyclist travels 26 miles in the same amount of time that the walker travels 6 miles the speed of the bicyclist. \n" ); document.write( ": \n" ); document.write( "The last part of the last sentence does not make much sense, but I assume they are asking for the actual speed of the bicyclist \n" ); document.write( ": \n" ); document.write( "Let s = speed of the bicyclist \n" ); document.write( "Then \n" ); document.write( "(s-10) = speed of the walker \n" ); document.write( ": \n" ); document.write( "They say the times of the two are equal, we can make a simple time equation from that fact: \n" ); document.write( "Time = Distance/speed \n" ); document.write( ": \n" ); document.write( "Bike time = Walking time \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Cross multiply: \n" ); document.write( "26(s-10) = 6s \n" ); document.write( "26s - 260 = 6s \n" ); document.write( "26s - 6s = +260 \n" ); document.write( "20s = 260 \n" ); document.write( "s = 260/20 \n" ); document.write( "s = 13 mph is the speed of the bike \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check our solution by confirming the times are equal: \n" ); document.write( "Walker speed: 13 - 10 = 3 mph \n" ); document.write( "6/3 = 2 hrs \n" ); document.write( "26/13 = 2 hrs \n" ); document.write( " |