document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165761>Question 1165761</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor both equations (difference and sum of cubes)\r<BR>\n" );
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document.write( "1. (x-3)^3 + (3x-2)^3\r<BR>\n" );
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document.write( "2. (x^9/512) - 512 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790202 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790202\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a^3+b^3 factors into (a+b) (a^2-ab+b^2)\r<BR>\n" );
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document.write( "so {(x-3)+(3x-2)}* {(x-3)^2)-(x-3)(3x-2)+(3x-2)^2}\r<BR>\n" );
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document.write( "the other is<BR>\n" );
document.write( "{(x3/8)-8} * ((x^6/64)+x^3+64)}<BR>\n" );
document.write( "but the first can be factored as well<BR>\n" );
document.write( "{(x/2)-2} * {(x^2/4)+x+4}\r<BR>\n" );
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document.write( "and the whole thing is<BR>\n" );
document.write( "{(x/2)-2} * {(x^2/4)+x+4}*{((x^6/64)+x^3+64)} </SPAN>\n" );
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