document.write( "Question 1165704: The fast track company manufactures toy remote control race cars which it sells for $25 each the production costs for the company is $2100 per day plus $13 per race car how many race cars must they sell in one day to make a profit of $2700 \n" ); document.write( "
Algebra.Com's Answer #790179 by Theo(13342)\"\" \"About 
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let c equal the total cost.
\n" ); document.write( "let r equal the total revenue.
\n" ); document.write( "let p = the profit which is equal to r - c.
\n" ); document.write( "let x equal the number of cars sold.\r
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\n" ); document.write( "\n" ); document.write( "all figures are per day.
\n" ); document.write( "c = 13 * x + 2100
\n" ); document.write( "r = 25 * x
\n" ); document.write( "p = 25 * x - (13 * x + 2100) which is equal to 12 * x - 2100.\r
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\n" ); document.write( "\n" ); document.write( "when p = 2700, the p formula becomes:
\n" ); document.write( "2700 = 12 * x - 2100
\n" ); document.write( "add 2100 to both sides of the equation to get:
\n" ); document.write( "4800 = 12 * x
\n" ); document.write( "solve for x to get:
\n" ); document.write( "x = 4800 / 12 = 400\r
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\n" ); document.write( "\n" ); document.write( "when the number of cars sold is 400, they will make a profit of 2700 for the day.
\n" ); document.write( "to confirm, replace x with 400 in the equations.
\n" ); document.write( "r = 25 * x becomes r = 25 * 400 which becomes r = 10,000
\n" ); document.write( "c = 13 * x + 2100 wich becomes c = 13 * 400 + 2100 which becomes c = 5200 + 2100 which becomes c = 7300.
\n" ); document.write( "r - c becomes 10,000 - 7300 = 2700.\r
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\n" ); document.write( "\n" ); document.write( "the value of x = 400 is confirmed to be good.
\n" ); document.write( "your solution is that they have to sell 400 cars to make 2700 profit.\r
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