document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165655>Question 1165655</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ally has a coin jar that contains nickels and dimes. The number of dimes is four more than twice the number of nickels. If she has $13.40, how many of each coin does she have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790163 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, you can get some good mental exercise by solving this using logical reasoning and some mental arithmetic.<br><BR>\n" );
document.write( "(1) Take the 4 \"extra\" dimes and set them aside; then arrange the remaining coins into groups of 2 dimes and 1 nickel.<br><BR>\n" );
document.write( "(2) The value of the 4 dimes is $0.40; the value of all the coins is $13.40.  So the value of the groups of dimes and nickels is $13.00.<br><BR>\n" );
document.write( "(3) The value of 2 dimes and 1 nickel is $0.25, or 25 cents.  The number of those groups required to make $13.00, or 1300 cents, is 1300/25 = 52.<br><BR>\n" );
document.write( "(4) So there are 52 groups each containing 2 dimes and 1 nickel, plus the other 4 dimes.  That makes the number of dimes 2(52)+4 = 104+4 = 108 and the number of nickels 52.<br><BR>\n" );
document.write( "ANSWER: 108 dimes, 52 nickels.<br><BR>\n" );
document.write( "CHECK: 108(10)+52(5) = 1080+260 = 1340<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );