document.write( "Question 1165568: Please help!
\n" ); document.write( "Find four consecutive integers such that 5 times the opposite of the first is 5 greater than the product of -3 and the sum of the third and fourth.
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Algebra.Com's Answer #790140 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Please help!
\n" ); document.write( "Find four consecutive integers such that 5 times the opposite of the first is 5 greater than the product of -3 and the sum of the third and fourth.
\n" ); document.write( "Thanks.
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Let first number be F
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document.write( "Then 2nd, 3rd, and 4th are: F + 1, F + 2, and F + 3, respectively 
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document.write( "We then get: 5(- F) = - 3(F + 2 + F + 3) + 5
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document.write( "- 5F = - 3(2F + 5) + 5
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document.write( "- 5F = - 6F - 15 + 5
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document.write( "- 5F = - 6F - 10
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document.write( "- 5F + 6F = - 10
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document.write( "First number or \"highlight_green%28matrix%281%2C3%2C+F%2C+%22=%22%2C+-+10%29%29\"
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document.write( "You should now be able to find the other 3! \n" );
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