document.write( "Question 1165477: The side of a regular pentagon is 25 cm. If the radius of its inscribed circle is 15 cm, find the area of the pentagon.
\n" ); document.write( "a. 937.5 cm2 b. 784.6 cm2
\n" ); document.write( "c. 825.75 cm2 d. 857.65 cm2
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Algebra.Com's Answer #790019 by Boreal(15235)\"\" \"About 
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The circle hits the sides and itself has area of πr^2=225 π or 706.86 cm^2\r
\n" ); document.write( "\n" ); document.write( "Draw this and note the 10 triangles that may be made. We know that because the central angle of each of those is 36 degrees and 360/36=10.
\n" ); document.write( "They are 36 degrees, because the internal angles of the pentagon are each 108 degrees {(n-2)/n}*180, and the line from the center to the vertex of each angle bisects it, so that is where 54 degrees comes from.\r
\n" ); document.write( "\n" ); document.write( "The area of each triangle is (1/2) bh with base 12.5 (half the side's length) and height 15 (the radius), so each triangle has area 93.75 cm^2. There are 10 of them, and the total area is 937.5 cm^2
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