document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165512>Question 1165512</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9. At noon, Shelby leaves her house and drives 50<BR>\n" );
document.write( "mph to her grandmother’s house. Her brother,<BR>\n" );
document.write( "Swayze, leaves at 12:30 P.M. and drives<BR>\n" );
document.write( "55 mph. What is the maximum length of time<BR>\n" );
document.write( "after Shelby leaves that Shelby is at least<BR>\n" );
document.write( "15 miles ahead of Swayze? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790017 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790017\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Brother starts off 25 miles behind, which is a half hour at 50 mph.<BR>\n" );
document.write( "He drives 5 mph faster, so he is closing the gap at 5 mph.<BR>\n" );
document.write( "After two hours he will be 15 miles behind, since he will have gained 10 miles<BR>\n" );
document.write( "The maximum length of time after Shelby leaves that she is at least 15 miles ahead ENDS at 2:30 pm.<BR>\n" );
document.write( "It began after she was 15 miles away.<BR>\n" );
document.write( "50 mph is 5/6 mile per minute<BR>\n" );
document.write( "15/(5/6)=18 minutes to go 15 miles at that speed.<BR>\n" );
document.write( "So the maximum length of time is from 12:18 pm to 2:30 pm or 2h12 m. </SPAN>\n" );
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