document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165528>Question 1165528</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of a 20% antifreeze solution and a 15% antifreeze solution must be mixed to obtain  30 gal of a 19% antifreeze solution? Round to the nearest gallon, if necessary. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #790012 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=790012\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x gal of 20%<BR>\n" );
document.write( "30-x gal of 15%<BR>\n" );
document.write( "30 gal of 19%=5.7 gal pure antifreeze<BR>\n" );
document.write( "the sum of the other two are .20x+0.15(30-x)=.20x+4.5-0.15x<BR>\n" );
document.write( "so 0.05x+4.5=5.7<BR>\n" );
document.write( "0.05x=1.2<BR>\n" );
document.write( "x=24 gal of 20%. (4.8 gal pure)<BR>\n" );
document.write( "30-x=6 gal of 15% (0.9 gal pure)\r<BR>\n" );
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document.write( "Check 19 is 1/5 of the way from 20 to 15, and 1/5 of 30 is 6 gal of the 15%. It is weighted much more towards the 20% antifreeze.<BR>\n" );
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