document.write( "Question 1165480: Find the area of a hexagon with a square having an area of 72 sq. cm. inscribed in a circle which is inscribed in a hexagon.
\n" ); document.write( "a. 124.71 sq. cm. b. 150.26 sq. cm. c. 150.35 sq. cm. d. 130.77 sq. cm.
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Algebra.Com's Answer #789999 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Note the statement of the problem should specify a REGULAR hexagon; without that, the problem is not defined well enough to get an answer.

\n" ); document.write( "Area of square which is inscribed in the circle: 72

\n" ); document.write( "Side of square: \"sqrt%2872%29+=+6%2Asqrt%282%29\"

\n" ); document.write( "Diagonal of square = diameter of circle: \"%286%2Asqrt%282%29%29%2Asqrt%282%29+=+12\"

\n" ); document.write( "The circle is inscribed in the hexagon; the diameter of the circle is the distance from the middle of one side of the hexagon to the middle of the opposite side.

\n" ); document.write( "View the hexagon as being composed of 6 equilateral triangles. The radius of the circle, length 12/2=6, is the long leg of a 30-60-90 right triangle in which the hypotenuse is the length of one side of one of those equilateral triangles.

\n" ); document.write( "Side length of hexagon = side length of one of the equilateral triangles = \"6%2A%282%2Fsqrt%283%29%29+=+12%2Fsqrt%283%29+=+4%2Asqrt%283%29\"

\n" ); document.write( "Area of hexagon = area of 6 equilateral triangles = \"6%28%28s%5E2%2Asqrt%283%29%29%2F4%29+=+6%28%2848sqrt%283%29%29%2F4%29+=+72sqrt%283%29\" = 124.71 to 2 decimal places.

\n" ); document.write( "ANSWER: a. 124.71 sq cm

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