document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165411>Question 1165411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tom Jones and Bill Smith set out to create their own thermometers.  Jones calls the freezing point of water on his scale 40 degrees, while Smith calls his freezing point 25 degrees.  Jones makes the boiling point of water 280 degrees and Smith, 125 degrees.  What temperature is on the Smith thermometer when the Jones thermometer reads 97 degrees?  Answer to the nearest tenth of a degree.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789977 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Jones scale: Freezing point = 40, Boiling point = 280<BR>\n" );
document.write( "Smith scale: Freezing point = 25, Boiling point = 125<BR>\n" );
document.write( "We need to find a relationship between the two scales<BR>\n" );
document.write( "On the Jones scale, the difference between boiling and freezing is 280 - 40 = 240<BR>\n" );
document.write( "On the Smith scale, the difference between boiling and freezing is 125 - 25 = 100<BR>\n" );
document.write( "Thus, the Jones scale has 240/100 = 2.4 degrees for every 1 degree on the Smith scale<BR>\n" );
document.write( "J = 2.4S + T0, where T0 is the yet to be determined intercept<BR>\n" );
document.write( "Use one of the given points to determine T0<BR>\n" );
document.write( "40 = 2.4*25 + T0 -> T0 = -20<BR>\n" );
document.write( "So J = 2.4S - 20<BR>\n" );
document.write( "97 = 2.4S - 20<BR>\n" );
document.write( "S = 117/2.4 = 48.8 deg. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );