document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165451>Question 1165451</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. [Round your answers to three decimal places, for example: 0.123]\r<BR>\n" );
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document.write( "Compute the probability that a randomly selected peanut M&M is not orange.\r<BR>\n" );
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document.write( "Compute the probability that a randomly selected peanut M&M is brown or orange.\r<BR>\n" );
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document.write( "Compute the probability that two randomly selected peanut M&M’s are both green.\r<BR>\n" );
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document.write( "If you randomly select six peanut M&M’s, compute that probability that none of them are red.\r<BR>\n" );
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document.write( "If you randomly select six peanut M&M’s, compute that probability that at least one of them is red.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789942 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789942\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. 23% are orange so 0.77 probability not orange.\r<BR>\n" );
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document.write( "b. brown or orange is 0.35 probability \r<BR>\n" );
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document.write( "c. both green would be (15/100)*14/99=0.0212\r<BR>\n" );
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document.write( "d. none is red when 6 chosen<BR>\n" );
document.write( "denominator is 100C6, number of ways to choose 6 out of a 100.<BR>\n" );
document.write( "88 out of 100 are not red<BR>\n" );
document.write( "so 88C6 are ways to pick one of those.\r<BR>\n" );
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document.write( "it is 88C6/100C6=0.4546\r<BR>\n" );
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document.write( "way 2<BR>\n" );
document.write( "88/100 probability first is not red*87/99*86/98*85/97*84/96*83/95=0.4546\r<BR>\n" );
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document.write( "e. at least one of them is red is the complement, since it is a dichotomy, and that probability is 0.5454.\r<BR>\n" );
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