document.write( "Question 108325: Mix a solution that is 50% acid with a solution that is 100% water to make 4L of a solution that is 10% acid. How much of each solution do you use? \n" ); document.write( "
Algebra.Com's Answer #78992 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Mix a solution that is 50% acid with a solution that is 100% water to make 4L of a solution that is 10% acid. How much of each solution do you use? \n" ); document.write( "---------- \n" ); document.write( "Just keep track of the acid. \n" ); document.write( "------------ \n" ); document.write( "50% solution DATA: \n" ); document.write( "Amount = x liters ; amt of acid = (1/2)x liters \n" ); document.write( "--------------- \n" ); document.write( "100% water DATA: \n" ); document.write( "Amount = \"4-x\" liters ; amt of acid = 0 \n" ); document.write( "--------------- \n" ); document.write( "10% solution DATA: \n" ); document.write( "Amount = 4 liters ; amt of acid = 0.40 liters \n" ); document.write( "---------------- \n" ); document.write( "EQUATION: \n" ); document.write( "acid + acid = acid \n" ); document.write( "(1/2)x + 0 = 0.40 \n" ); document.write( "x = 0.8 liters \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |