document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165429>Question 1165429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 3 less than twice its length. If the area of the rectangle is 33  <BR>\n" );
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document.write( " , what is the length of the diagonal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789919 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 3 less than twice its length. If the area of the rectangle is 33 cm^2<BR>\n" );
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document.write( "L*W = 33<BR>\n" );
document.write( "L = 2W - 3<BR>\n" );
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document.write( "W*(2W-3) = 33<BR>\n" );
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document.write( "Solve for W, then find L<BR>\n" );
document.write( "Then find the diagonal.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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