document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1165429>Question 1165429</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 3 less than twice its length. If the area of the rectangle is 33  <BR>\n" );
document.write( "cm^2\r<BR>\n" );
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document.write( " , what is the length of the diagonal? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #789918 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=789918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length=x<BR>\n" );
document.write( "width is 2x-3\r<BR>\n" );
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document.write( "area is 33 so 2x^2-3x=33<BR>\n" );
document.write( "2x^2-3x-33=0<BR>\n" );
document.write( "x=(1/4) (3+/- sqrt (9+264)); sqrt (273)=16.52<BR>\n" );
document.write( "only positive root is x=4.88 cm<BR>\n" );
document.write( "so length is 4.88 cm and width is 6.76 cm. Their product is 32.99 cm^2\r<BR>\n" );
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document.write( "the diagonal is the sqrt (4.88^2+6.76^2)=8.34 cm<BR>\n" );
document.write( "  </SPAN>\n" );
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