document.write( "Question 1165401: An auto A is moving at 30 fps and accelerating at 5 fps^2 to overtake an auto B
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document.write( "which is 384 ft ahead. Auto B is moving at 60 fps and decelerating at 3 fps^2
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document.write( "(a) How soon will A pass B?
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document.write( "(b) What is the total distance traveled by car A? \n" );
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Algebra.Com's Answer #789893 by Theo(13342)![]() ![]() You can put this solution on YOUR website! i believe the distance formula for an accelerating car is y = ax + (b/2)x^2 and the distance formula for a decelerating car is y = ax - (b/2)x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x is the number of seconds. \n" ); document.write( "y is the distance traveled in x seconds. \n" ); document.write( "a is the constant velocity \n" ); document.write( "b is the constant constant acceleration.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "applying this to your situation gets you.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 30 * x + 5/2 * x^2 for the accelerating car.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "y = 60 * x - 3/2 * x^2 for the decelerating car.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both cars will have traveled the same distance when 30 * x + 5/2 * x^2 = 60 * x - 3/2 * x^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 7.5 seconds.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both cars will have traveled the same distance in 7.5 seconds, after w hich the accelerating car will have passed the decelerating car.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at this point in time, the distanced traveled by each car will be 365.625 feet.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equations for each car can be graphed. \n" ); document.write( "the intersection of the lines on the graph is when both cars will have traveled the same distance.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation for the accelerating car is y = 30x + 5/2 * x^2. \n" ); document.write( "the equation for the decelerating cvar is y = 60x - 3/2 * x^2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph confirms the solution expressed above (365.625 feet in 7.5 seconds for both cars).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i also used a calculator to confirm the formulas were correctly applied.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for the accelerating car .....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "for the decelerating car .....\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both the graph and the calculator confirm the calculations are correct.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this assumes, of course, that i'm using the right formula. \n" ); document.write( "i'm reasonably confident that i am.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |